Multiple Choice Questions (M.C.Qs) MDCAT Topic #2 Motion and Forces
Q.1 At which angle,the K.E at maximum height will be 25 % of its initial K.E
A) 30'
B) 45'
C) 60'
D) 90'
Q.2 A body moves in semicircle of radius 'r'.The ratio of displacement to distance is
A) π/2
B) 2/π
C) 3/π
D) 4π
Q.3 A car is going on motorway from Lahore to Islamabad ,suddenly its accelerater and breaks fail then in which direction impulse will be with velocity
A) 90 degree
B) 180 degree
C) 0 degree
D) 45 degree
Q.4 At maximum height of projectile,the angle between velocity and acceleration will be
A) 90
B) 180
C) 270
D) 360
Q.5 When the slope of velocity time graph is zero,it means which quantity must be zero
A) Displacement
B) Velocity
C) Acceleration
D) Mass
Answers :
Q.1 C
Q.2 B
Q.3 B
Q.4 A
Q.5 £
Explanations:
Q.1
Answer is 60 degree because at maximum height only horizontal component is there,when we will put the 60 degree angle in K.E formula at maximum height we will get 1/4 of initial K.E
Q.2
Solution:
Use formula
2r / πr
When the body moves in semicicle then we get answer by dividing 2r/πr.Hence B is correct option.
Q.3
In this case because breaks and acceleraters are totaly failed so only road friction is there due to which impulse and velocity will have 180 degree angle with each other.
Q.4
At highest point velocity is horizontal and acceleration is always vertical.Hence angle always be 90 degree at maximum height
Q.5
Answers :
Q.1 C
Q.2 B
Q.3 B
Q.4 A
Q.5 £
Explanations:
Q.1
Answer is 60 degree because at maximum height only horizontal component is there,when we will put the 60 degree angle in K.E formula at maximum height we will get 1/4 of initial K.E
Q.2
Solution:
Use formula
2r / πr
When the body moves in semicicle then we get answer by dividing 2r/πr.Hence B is correct option.
Q.3
In this case because breaks and acceleraters are totaly failed so only road friction is there due to which impulse and velocity will have 180 degree angle with each other.
Q.4
At highest point velocity is horizontal and acceleration is always vertical.Hence angle always be 90 degree at maximum height
Q.5
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